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4m^2-24m+35=0
a = 4; b = -24; c = +35;
Δ = b2-4ac
Δ = -242-4·4·35
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4}{2*4}=\frac{20}{8} =2+1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4}{2*4}=\frac{28}{8} =3+1/2 $
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